If you have suggestions to make it better, this will be welcome too I know that this map can be improved (I suck at drawing and I didn't have so much time to do it), but any opinion would be appreciated (even a negative one: if you think this is too complex, you can tell me). This is slightly less than the direct transfer that would cost 377 m/s. Now, the second maneuver, I burn retrograde at the apoapsis, which costs 19+19=38m/s:įinally, the third maneuver, which costs 230+44+18=292m/s (can be reduced by aerobraking): The normal transfer is the red path, the bi-elliptic one is the blue path.įirst step consists in burning so that I approach the SOI limit: Now, let's try that bi-elliptic transfer instead: 44+230=274m/s to circularize at Mars level (can be done by mostly aerobraking)
2+37+64=103m/s (yellow branch) to put my ship on the transfer orbit Now let's suppose I'm orbiting Deimos and I want to go back to LMO: Then the second step is satellization around Phobos:Īccording to the map, this costed 118+3 = 121 m/s. I'll join Phobos with a normal transfer trajectory, which corresponds to this path:įirst step is burning at Mars level to put my ship on the transfer trajectory. The fourth one is a transfer orbit which periapsis is at LMO level and apoapsis near the SOI limit. Similarly, the second node is the transfer orbit between LMO and Deimos, and the third one between Phobos and Deimos. You can deduce this from the fact that this node is at the crossroads of Mars and Phobos branches.
For example, the node n☁ is the transfer orbit between Low Mars Orbit (LMO) and Phobos. What is probably not clear is those nodes in the middle: Meanwhile, here are a few explanations.įirst, I suppose that the "orbit" nodes are not a problem. Thanks for the feedback, I understand it looks complicated, I'll draw a simplified map with only direct transfers, which should help a lot.
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